Re: [問題] 一個複雜的排列組合問題

看板puzzle (益智遊戲 - 數獨,拼圖,推理,西洋棋)作者 (IWH68S0XZ8M89)時間18年前 (2008/02/07 13:36), 編輯推噓3(300)
留言3則, 3人參與, 最新討論串3/3 (看更多)
昨晚守歲看電影太累了Orz 所以弄錯了 應該是這樣: 由排容原理得10個客人恰選了n種的選法有 n-1 i 10 C(8,n)* Σ (-1) * C(n,i)*(n-i) i=0 例如恰選了1種的選法是 C(8,1)*1^10 恰選了2種的選法是 C(8,2)*(2^10-2*1^10) 恰選了3種的選法是 C(8,3)*(3^10-3*2^10+3*1^10) etc. 因此所求答案就是 1 8 n-1 i 10 ------ Σ n*C(8,n)*Σ (-1) * C(n,i)*(n-i) 8^10 n=1 i=0 這樣Mathematica求出來的也是5.89多了 -- 但是我目前還想不到怎麼化簡 Orz -- 'You've sort of made up for it tonight,' said Harry. 'Getting the sword. Finishing the Horcrux. Saving my life.' 'That makes me sound a lot cooler then I was,' Ron mumbled. 'Stuff like that always sounds cooler then it really was,' said Harry. 'I've been trying to tell you that for years.' -- Harry Potter and the Deathly Hollows, P.308 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 219.84.44.21 ※ 編輯: LPH66 來自: 219.84.44.21 (02/07 13:36)

02/07 21:34, , 1F
厲害~
02/07 21:34, 1F

02/07 22:46, , 2F
原來是我把排容式子弄得太複雜了..真強!佩服佩服~
02/07 22:46, 2F

02/11 00:10, , 3F
8*[1-(7/8)^10] 不過不太好敘述...
02/11 00:10, 3F
文章代碼(AID): #17gfZAPc (puzzle)
文章代碼(AID): #17gfZAPc (puzzle)