Re: [閒聊] 關於王飾
看板ELSWORD (艾爾之光)作者jackerxx (((o(#+>"<)==o)))時間15年前 (2011/02/11 10:19)推噓11(11推 0噓 22→)留言33則, 13人參與討論串2/2 (看更多)
本日最無用....
假設掉寶率=X,則不掉寶率Y=1-X
在每個人的骰子(人品)皆相同的情形下,
中寶機率 = (1/N)*(1-Y^M) ,N為人數,M為掉落判定
孤軍奮戰 = (1/1)*(1-Y^1) ,用1-不會掉落的可能性=掉落可能,再除以人數平分
兩個恰恰好 = (1/2)*(1-Y^1)
三P = (1/3)*(1-Y^2)
四人圍爐 = (1/4)*(1-Y^2).........感謝U大指正
==============================不正常研究中心分隔線============================
在骰子公平公正公開的情況下,
掉寶率100% 90% 80% 70% 60% 50% 40% 30% 20% 10% 5% 3% 2% 1%
1P 100% 90% 80% 70% 60% 50% 40% 30% 20% 10% 5% 3% 2% 1%
2P 50% 45% 40% 35% 30% 25% 20% 15% 10% 5% 2.5% 1.5% 1% 0.5%
3P 33.3% 33% 32% 30% 28% 25% 21% 17% 12% 6.3% 3.3% 2% 1.3% 0.66%
4P 25% 24.8% 24% 22.8% 21% 18.8% 16% 12.8% 9% 4.8% 2.4% 1.5% 0.99% 0.5%
把骰子因素加進去→人品係數R
用R取代式中的(1/N) → R*(1-Y^M)
單刷不影響 R=1
2P
人品HIGH
↑ 6 R=(隊友骰6)+(隊友骰1~5)
│ =(1/6)*(1/2)+(5/6)*1 =92%
│ 5 R=(隊友骰6)+(隊友骰5)+(隊友骰1~4)
│ =(1/6)*0+(1/6)*(1/2)+(4/6)*1 =75%
│ 4 R=(2/6)*0+(1*6)*(1/2)+(3/6)*1 =58%
│ →整合公式為R=1/12+(K-1)/6
│ 3 R=........................... =42% K=自己骰的數字
│
│ 2 R=........................... =25%
│
↓ 1 R=........................... = 8%
人品LOW
3P
人品HIGH
↑ 6 R=(隊友二人都骰6)+(隊友一人骰6、一人骰1~5)+(隊友二人都骰1~5)
│ =(1/6)^2*(1/3)+(1/6)*(5/6)*2*(1/2)+(5/6)^2*1=84%
│ 5 R=(其中一人骰6)+(都骰5)+(一骰5、一骰1~4)+(都骰1~4)
│ =(11/36)*0+(1/6)^2*(1/3)+(1/6)*(4/6)*2*(1/2)+(4/6)^2*1=56%
│ 4 R=(20/36)*0+(1/6)^2*(1/3)+(1/6)*(3/6)*2*(1/2)+(3/6)^2*1=34%
│
│ 3 R=.....................................................=18%
│
│ 2 R=.....................................................= 6%
│
↓ 1 R=.....................................................= 1%(0.93%)
人品LOW
→整合公式為 R=1/108+(K-1)/36+((K-1)^2)/36
4P
人品HIGH
↑ 6 R=(沒人骰6)+(一人骰6)+(二人骰6)+(都骰6)
│ =(5/6)^3*1+(1/6)*(5/6)^2*3*(1/2)+(1/6)^2*(5/6)*3*(1/3)+(1/6)^3*(1/4)
│ =78%
│ 5 R=(其中一人骰6)+[(沒人骰5)+(一人骰5)+(二人骰5)+(都骰5)]U沒人骰6
│ =0(好難算喔!)+(4/6)^3*1+(1/6)*(4/6)^2*3*(1/2)+巴拉巴拉巴拉
│ =43%
│ 4 R=...........................................
│ =20%
│
│ 3 R=...........................................
│ = 8%
│
│ 2 R=...........................................
│ =1.7%
│
↓ 1 R=...........................................
=0.1%(囧)
人品LOW →整合公式 R =((K-1)/6)^3*1+(1/6)*((K-1)/6)^2*3*(1/2)
+(1/6)^2*((K-1)/6)*3*(1/3)+(1/6)^3*(1/4)
至於(1-Y^M)就會變成
掉寶率100% 90% 80% 70% 60% 50% 40% 30% 20% 10% 5% 3% 2% 1%
1~2P 100% 90% 80% 70% 60% 50% 40% 30% 20% 10% 5% 3% 2% 1%
3~4P 100% 99% 96% 91% 84% 75% 64% 51% 36% 19% 9.8% 5.9% 3.96% 1.99%
結論:1.人品還是決定一切,EX:0.5%<<1.55%,還沒考慮骰子連吸功能哦^.<
2.黑橘別再製造杯具了。
3.數學狂派不要K我,有錯請鞭小力一點,不要打臉@@...謝謝> <
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◆ From: 114.36.162.188
※ 編輯: jackerxx 來自: 114.36.162.188 (02/11 10:21)
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※ 編輯: jackerxx 來自: 114.36.162.188 (02/11 11:28)
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我懂了!推文裡的是結果,難怪我一開始誤會成掉落率X2 XD
1人 %=(1/1)*(1-(1-X)^1)=X
2人 %=(1/2)*(1-(1-X)^1)=X/2
3人 %=(1/3)*(1-(1-X)^2+X^2)=2X/3
^^^^^^^^^ ^^^
4人 %=(1/4)*(1-(1-X)^2+X^2)=X/2
^^^^^^^^^ ^^^
掉一個的機率 掉兩個的機率
※ 編輯: jackerxx 來自: 114.36.162.188 (02/11 11:53)
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02/11 11:54, , 28F
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反正只要記住一個原則,人品萬歲萬萬歲就對啦!!大家一起來培養人品吧XD
※ 編輯: jackerxx 來自: 114.36.162.188 (02/11 12:47)
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02/11 12:49, , 32F
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※ 編輯: jackerxx 來自: 114.36.162.188 (02/11 12:55)
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02/11 20:37, , 33F
02/11 20:37, 33F
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