[資訊] harddrop討論全消perfect clear

看板tetris (俄羅斯方塊 - Tetris)作者buzz1067 (buzz1067)時間13年前 (2011/08/09 08:50)推噓5(5推 0噓 4→)

留言9則, 5人參與討論串1/1

俄羅斯方塊討論全消(perfect clear)技巧引述自www.harddrop.com的會員 *引述自Harddrop的Xenoslah(quoted from Xenoslash from Harddrop) DO NOT TRY with 3, 2 or 1 blocks. " I might have misunderstood this statement , but I thought it's impossible to have an odd number of blocks in the matrix? -To build, multiples of 4, lines clears, multiple of 10, so always even number of blocks in the matrix. "Also, it is impossible to get 1, 3, 5, etc., cells left on the board." I was wondering why raven would state that it's impossible to get a pc with 1,3,5 cells when it's impossible to get an odd number of cells. (you stack + multiples of 4. Clear lines. multiples of 10) "he meant minos. like what makes up a tetromino." mino = the cells question mark is talking about? And I accidentally clicked report questionmark lol. Sorry! Oh, and like what questionmark said. I am talking about practice mode. So no weird garbage and stuff. EDIT: "Not only is it possible to get a PC with 2 remaining cells...it's necessary to use an odd number of line clears to do so, no matter how many line clears it takes to get the PC from there." 2 cells + 4 * number of pieces = 10 * n . 1 + 2p = 5n If n is even. 10(n/2) = 1+2p n/2 = (1+2p)/ 10 = 0.1 + p/5 no integer value for p exists to make n/2 an integer. Hence, n cannot be even if n is odd, let n = (k-1)/2 1+2p = 5/2(k-1) 5k-5 = 2+4p 5k = 7 + 4p k = (7+4p)/5 p = 2, 7, 12 , etc p = 2 + 5C, where C is an integer >= 0 Hence. You need 2 + 5C pieces to get the odd number of lines clears to get PC. Yay! -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 118.168.89.237