[中譯] Puzzleup 2012 (6) Three Pawns in a Frame

看板puzzle (益智遊戲 - 數獨,拼圖,推理,西洋棋)作者 (杇瑣)時間13年前 (2012/08/30 00:46), 編輯推噓1(100)
留言1則, 1人參與, 最新討論串1/1
題目網址: http://www.puzzleup.com/2012/?home http://www.puzzleup.com/2012/puzzle/?247 答題時限: 8月30日7PM-比賽結束(約12月12日) 加分時限: 8月30日7PM-9月4日6:59PM 答對可得基本分100分。答案可上傳5次,每改1次答案從基本分扣20分 另有兩種加分: 1. 加分時限內答對。例:第N天答對,可加(6-N)分。 2. 題目越困難,加分越多。例:這題有n%的人答錯,答對者加n分。 ◆Three Pawns in a Frame There is a square wire frame with a side length of X units (integer), a chessboard with a side length of 8 units, and 33 pawns to be placed randomly on this board. What is the minimum value for X, if it is possible to place the frame on the board to cover at least 3 pawns, for every possible placement of the 33 pawns on the board. Note: For the frame to cover a pawn, it needs to fully cover the square the pawn is on. 有一個正方形框架,邊長為 X 單位(X 為整數),一個邊長為八單位的西洋棋盤, 以及隨機在這盤子上放置的 33 個小兵。 求 X 的最小值,使得無論這 33 個小兵在盤上怎麼擺, 都能夠將這框架放在棋盤上,使得它框住至少三個小兵。 注意:要使這個框架框住某個小兵,它必須完全包含該小兵所在的方格。 -- 雖然沒有明說,但這樣子的敘述方式我覺得應該這正方框只能貼格線放... (也就是說沒有那種搞怪的斜放法就是了) 這樣一來這題似乎沒什麼好玩的 (思) 9/5 edit: 新題快出了才看到原題補了個跟我的猜測差不多的 Note... 我也補上去好了 (思 -- 'You've sort of made up for it tonight,' said Harry. 'Getting the sword. Finishing the Horcrux. Saving my life.' 'That makes me sound a lot cooler then I was,' Ron mumbled. 'Stuff like that always sounds cooler then it really was,' said Harry. 'I've been trying to tell you that for years.' -- Harry Potter and the Deathly Hollows, P.308 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 180.218.108.125

08/30 01:49, , 1F
既然規定X是整數,亂放也不影響答案吧...而且33這數字明顯故意
08/30 01:49, 1F
※ 編輯: LPH66 來自: 180.218.108.125 (09/05 18:48)
文章代碼(AID): #1GFaTBzP (puzzle)
文章代碼(AID): #1GFaTBzP (puzzle)