Re: [功課] 借我問一下 囧
※ 引述《DongROD (斑龍丸˙六淑幾像六年級)》之銘言:
: 有一輛跑車,停在汽車代理商的展示場裡,天空中有一架貨機以50公尺/秒水平
: 飛過,當這架貨機在跑車正上方125公尺處經過的瞬間,
: 有一箱貨物突然從運輸機的艙門掉了出來,
: 相對於這輛跑車,請問這箱貨物會掉到何處幾公尺??
自由落體公式
H=1/2*g*t^2
而
H=125 m
g=9.8 m/s^2
所以
t=5.051
等速度運動公式
s=v*t
t=5.051
v=50 m/s
所以
s=252.5381 m
Ans: 貨物掉落處距離跑車 252.5381 m
家教費 NT:500元拿來
然後指考加油
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